I believe i did an error in my earlier math so disregard.
650 x log10((650 / 644 + 1) ^ 0.x + 1)
= 213
for this I am getting x = 0.17
To solve this just requires a little algebraic manipulation and knowledge of logarithmic properties.
First: divide 213 by 650
213/650 = log((650/644 + 1)^x +1)
Second: since its base 10, you set both sides as exponents of 10 and solve, canceling out the log on the right
10^(213/650) =2.12663 = (650/644 + 1)^x +1
Third: Subtract 1 from both sides
1.12663 = (650/644 +1)^x
Fourth: Take the natural log of each side(doesn’t really matter if its base e or 10 or whatever)
ln(1.12663)= ln(650/644 + 1)^x
Since its a log you can bring the exponent down as a factor
ln(1.12663)=x * ln(650/644 + 1)
and simplify
ln(1.12663)/ln(650/644 + 1) = x
0.170868…= x

